144m^2+0m-196=0

Solution for 144m^2+0m-196=0 equation:

144m^2+0m-196=0

We add all the numbers together, and all the variables

144m^2+m-196=0

a = 144; b = 1; c = -196;
Δ = b2-4ac
Δ = 12-4·144·(-196)
Δ = 112897
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{112897}}{2*144}=\frac{-1-\sqrt{112897}}{288}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{112897}}{2*144}=\frac{-1+\sqrt{112897}}{288}
$